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101102200121147 is a prime number
BaseRepresentation
bin10110111111001110110000…
…101110010110011100111011
3111020222021110011022000211212
4112333032300232112130323
5101222424301212334042
6555005413132313335
730203251524452201
oct2677166056263473
9436867404260755
10101102200121147
112a23a22526a805
12b40a34a31284b
134454b86995a44
141ad7530589071
15ba4d784b3482
hex5bf3b0b9673b

101102200121147 has 2 divisors, whose sum is σ = 101102200121148. Its totient is φ = 101102200121146.

The previous prime is 101102200121081. The next prime is 101102200121183. The reversal of 101102200121147 is 741121002201101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101102200121147 - 28 = 101102200120891 is a prime.

It is a super-3 number, since 3×1011022001211473 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (101102200120147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551100060573 + 50551100060574.

It is an arithmetic number, because the mean of its divisors is an integer number (50551100060574).

Almost surely, 2101102200121147 is an apocalyptic number.

101102200121147 is a deficient number, since it is larger than the sum of its proper divisors (1).

101102200121147 is an equidigital number, since it uses as much as digits as its factorization.

101102200121147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 23.

Adding to 101102200121147 its reverse (741121002201101), we get a palindrome (842223202322248).

The spelling of 101102200121147 in words is "one hundred one trillion, one hundred two billion, two hundred million, one hundred twenty-one thousand, one hundred forty-seven".