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101102222111330 = 2511919111110103
BaseRepresentation
bin10110111111001110110010…
…000010001111001001100010
3111020222021111200200020201002
4112333032302002033021202
5101222424322330030310
6555005415235512002
730203252212410416
oct2677166202171142
9436867450606632
10101102222111330
112a23a23671a310
12b40a355758602
134454b8b3c4c9b
141ad7533470d46
15ba4d7a3a8da5
hex5bf3b208f262

101102222111330 has 16 divisors (see below), whose sum is σ = 198527999782464. Its totient is φ = 36764444404080.

The previous prime is 101102222111323. The next prime is 101102222111377. The reversal of 101102222111330 is 33111222201101.

It is a super-4 number, since 4×1011022221113304 (a number of 57 digits) contains 4444 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 459555554942 + ... + 459555555161.

It is an arithmetic number, because the mean of its divisors is an integer number (12407999986404).

Almost surely, 2101102222111330 is an apocalyptic number.

101102222111330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101102222111330 is a deficient number, since it is larger than the sum of its proper divisors (97425777671134).

101102222111330 is a wasteful number, since it uses less digits than its factorization.

101102222111330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 919111110121.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 101102222111330 its reverse (33111222201101), we get a palindrome (134213444312431).

The spelling of 101102222111330 in words is "one hundred one trillion, one hundred two billion, two hundred twenty-two million, one hundred eleven thousand, three hundred thirty".

Divisors: 1 2 5 10 11 22 55 110 919111110103 1838222220206 4595555550515 9191111101030 10110222211133 20220444422266 50551111055665 101102222111330