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101103002113 = 1993259155893
BaseRepresentation
bin101111000101000110…
…1010110001000000001
3100122222001010122200211
41132022031112020001
53124024332031423
6114240204114121
710206266224051
oct1361215261001
9318861118624
10101103002113
11399720109a3
1217717235941
1396c31a1a09
144c71741561
15296aeb510d
hex178a356201

101103002113 has 8 divisors (see below), whose sum is σ = 101642888000. Its totient is φ = 100563434928.

The previous prime is 101103002057. The next prime is 101103002149. The reversal of 101103002113 is 311200301101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101103002113 - 225 = 101069447681 is a prime.

It is a super-2 number, since 2×1011030021132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101103002093 and 101103002102.

It is not an unprimeable number, because it can be changed into a prime (101103002713) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 570595 + ... + 726487.

It is an arithmetic number, because the mean of its divisors is an integer number (12705361000).

Almost surely, 2101103002113 is an apocalyptic number.

It is an amenable number.

101103002113 is a deficient number, since it is larger than the sum of its proper divisors (539885887).

101103002113 is a wasteful number, since it uses less digits than its factorization.

101103002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159351.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 101103002113 its reverse (311200301101), we get a palindrome (412303303214).

The spelling of 101103002113 in words is "one hundred one billion, one hundred three million, two thousand, one hundred thirteen".

Divisors: 1 199 3259 155893 648541 31022707 508055287 101103002113