Base | Representation |
---|---|
bin | 11101011011001100101… |
… | …10000100100111011101 |
3 | 10120122122201112211122102 |
4 | 32231212112010213131 |
5 | 113031044300023134 |
6 | 2052243543254445 |
7 | 133021242256262 |
oct | 16554626044735 |
9 | 3518581484572 |
10 | 1011034376669 |
11 | 35a860603459 |
12 | 143b4144a425 |
13 | 7445636b2c5 |
14 | 36d11b05269 |
15 | 1b47534637e |
hex | eb665849dd |
1011034376669 has 2 divisors, whose sum is σ = 1011034376670. Its totient is φ = 1011034376668.
The previous prime is 1011034376663. The next prime is 1011034376707. The reversal of 1011034376669 is 9666734301101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 998026974169 + 13007402500 = 999013^2 + 114050^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011034376669 - 28 = 1011034376413 is a prime.
It is a super-2 number, since 2×10110343766692 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011034376663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505517188334 + 505517188335.
It is an arithmetic number, because the mean of its divisors is an integer number (505517188335).
Almost surely, 21011034376669 is an apocalyptic number.
It is an amenable number.
1011034376669 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011034376669 is an equidigital number, since it uses as much as digits as its factorization.
1011034376669 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 489888, while the sum is 47.
The spelling of 1011034376669 in words is "one trillion, eleven billion, thirty-four million, three hundred seventy-six thousand, six hundred sixty-nine".
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