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10110440412013 is a prime number
BaseRepresentation
bin1001001100100000010100…
…1101011001001101101101
31022210112210222100110220111
42103020011031121031231
52311122140221141023
633300401110220021
72062312065351634
oct223100515311555
938715728313814
1010110440412013
1132488a50411a7
12117357a054611
13584544975c46
1426d4c29d651b
15127ee0a3300d
hex9320535936d

10110440412013 has 2 divisors, whose sum is σ = 10110440412014. Its totient is φ = 10110440412012.

The previous prime is 10110440412001. The next prime is 10110440412019. The reversal of 10110440412013 is 31021404401101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7403171649129 + 2707268762884 = 2720877^2 + 1645378^2 .

It is an emirp because it is prime and its reverse (31021404401101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10110440412013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110440412019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055220206006 + 5055220206007.

It is an arithmetic number, because the mean of its divisors is an integer number (5055220206007).

Almost surely, 210110440412013 is an apocalyptic number.

It is an amenable number.

10110440412013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110440412013 is an equidigital number, since it uses as much as digits as its factorization.

10110440412013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 10110440412013 its reverse (31021404401101), we get a palindrome (41131844813114).

The spelling of 10110440412013 in words is "ten trillion, one hundred ten billion, four hundred forty million, four hundred twelve thousand, thirteen".