Base | Representation |
---|---|
bin | 1001001100100000010100… |
… | …1101011001001101101101 |
3 | 1022210112210222100110220111 |
4 | 2103020011031121031231 |
5 | 2311122140221141023 |
6 | 33300401110220021 |
7 | 2062312065351634 |
oct | 223100515311555 |
9 | 38715728313814 |
10 | 10110440412013 |
11 | 32488a50411a7 |
12 | 117357a054611 |
13 | 584544975c46 |
14 | 26d4c29d651b |
15 | 127ee0a3300d |
hex | 9320535936d |
10110440412013 has 2 divisors, whose sum is σ = 10110440412014. Its totient is φ = 10110440412012.
The previous prime is 10110440412001. The next prime is 10110440412019. The reversal of 10110440412013 is 31021404401101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7403171649129 + 2707268762884 = 2720877^2 + 1645378^2 .
It is an emirp because it is prime and its reverse (31021404401101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10110440412013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10110440412019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055220206006 + 5055220206007.
It is an arithmetic number, because the mean of its divisors is an integer number (5055220206007).
Almost surely, 210110440412013 is an apocalyptic number.
It is an amenable number.
10110440412013 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110440412013 is an equidigital number, since it uses as much as digits as its factorization.
10110440412013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 10110440412013 its reverse (31021404401101), we get a palindrome (41131844813114).
The spelling of 10110440412013 in words is "ten trillion, one hundred ten billion, four hundred forty million, four hundred twelve thousand, thirteen".
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