10111020193 has 2 divisors, whose sum is σ = 10111020194. Its totient is φ = 10111020192.

The previous prime is 10111020173. The next prime is 10111020287. The reversal of 10111020193 is 39102011101.

10111020193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6827386384 + 3283633809 = 82628^2 + 57303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10111020193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10111020193.

It is not a weakly prime, because it can be changed into another prime (10111020173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055510096 + 5055510097.

It is an arithmetic number, because the mean of its divisors is an integer number (5055510097).

Almost surely, 2^10111020193 is an apocalyptic number.

It is an amenable number.

10111020193 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111020193 is an equidigital number, since it uses as much as digits as its factorization.

10111020193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10111020193 its reverse (39102011101), we get a palindrome (49213031294).

The spelling of 10111020193 in words is "ten billion, one hundred eleven million, twenty thousand, one hundred ninety-three".