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101110221212093 is a prime number
BaseRepresentation
bin10110111111010110001110…
…110100011000100110111101
3111021000001011011101200002022
4112333112032310120212331
5101223042213112241333
6555013221104205525
730203654352554042
oct2677261664304675
9437001134350068
10101110221212093
112a242670a33095
12b40ba086098a5
1344558646b19c2
141ad7a919831c9
15ba5197777c98
hex5bf58ed189bd

101110221212093 has 2 divisors, whose sum is σ = 101110221212094. Its totient is φ = 101110221212092.

The previous prime is 101110221212047. The next prime is 101110221212101. The reversal of 101110221212093 is 390212122011101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90676920688249 + 10433300523844 = 9522443^2 + 3230062^2 .

It is a cyclic number.

It is not a de Polignac number, because 101110221212093 - 242 = 96712174700989 is a prime.

It is a super-3 number, since 3×1011102212120933 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101110241212093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555110606046 + 50555110606047.

It is an arithmetic number, because the mean of its divisors is an integer number (50555110606047).

Almost surely, 2101110221212093 is an apocalyptic number.

It is an amenable number.

101110221212093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101110221212093 is an equidigital number, since it uses as much as digits as its factorization.

101110221212093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 26.

Adding to 101110221212093 its reverse (390212122011101), we get a palindrome (491322343223194).

The spelling of 101110221212093 in words is "one hundred one trillion, one hundred ten billion, two hundred twenty-one million, two hundred twelve thousand, ninety-three".