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101110221999973 is a prime number
BaseRepresentation
bin10110111111010110001110…
…110111011000111101100101
3111021000001011012212200212001
4112333112032313120331211
5101223042213312444343
6555013221133125301
730203654362345054
oct2677261667307545
9437001135780761
10101110221999973
112a24267142102a
12b40ba08929831
1344558648c94c4
141ad7a91b0a39b
15ba519788144d
hex5bf58edd8f65

101110221999973 has 2 divisors, whose sum is σ = 101110221999974. Its totient is φ = 101110221999972.

The previous prime is 101110221999953. The next prime is 101110221999977. The reversal of 101110221999973 is 379999122011101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83447896140324 + 17662325859649 = 9134982^2 + 4202657^2 .

It is a cyclic number.

It is not a de Polignac number, because 101110221999973 - 237 = 100972783046501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101110221999977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555110999986 + 50555110999987.

It is an arithmetic number, because the mean of its divisors is an integer number (50555110999987).

Almost surely, 2101110221999973 is an apocalyptic number.

It is an amenable number.

101110221999973 is a deficient number, since it is larger than the sum of its proper divisors (1).

101110221999973 is an equidigital number, since it uses as much as digits as its factorization.

101110221999973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 551124, while the sum is 55.

The spelling of 101110221999973 in words is "one hundred one trillion, one hundred ten billion, two hundred twenty-one million, nine hundred ninety-nine thousand, nine hundred seventy-three".