10111032034121 has 2 divisors, whose sum is σ = 10111032034122. Its totient is φ = 10111032034120.

The previous prime is 10111032034091. The next prime is 10111032034139. The reversal of 10111032034121 is 12143023011101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5182361190400 + 4928670843721 = 2276480^2 + 2220061^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111032034121 - 2³⁰ = 10109958292297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10111032034093 and 10111032034102.

It is not a weakly prime, because it can be changed into another prime (10111032034141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055516017060 + 5055516017061.

It is an arithmetic number, because the mean of its divisors is an integer number (5055516017061).

Almost surely, 2^{10111032034121} is an apocalyptic number.

It is an amenable number.

10111032034121 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111032034121 is an equidigital number, since it uses as much as digits as its factorization.

10111032034121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 10111032034121 its reverse (12143023011101), we get a palindrome (22254055045222).

The spelling of 10111032034121 in words is "ten trillion, one hundred eleven billion, thirty-two million, thirty-four thousand, one hundred twenty-one".