Base | Representation |
---|---|
bin | 10110111111010111000011… |
… | …110010111000010010111111 |
3 | 111021000010110002211021200001 |
4 | 112333113003302320102333 |
5 | 101223101023130310142 |
6 | 555013445214215131 |
7 | 30204015364325524 |
oct | 2677270362702277 |
9 | 437003402737601 |
10 | 101111110010047 |
11 | 2a242a87704155 |
12 | b4100161b44a7 |
13 | 4455976885657 |
14 | 1ad7b37a2514b |
15 | ba51ea7e05b7 |
hex | 5bf5c3cb84bf |
101111110010047 has 2 divisors, whose sum is σ = 101111110010048. Its totient is φ = 101111110010046.
The previous prime is 101111110010003. The next prime is 101111110010081. The reversal of 101111110010047 is 740010011111101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101111110010047 - 243 = 92315016987839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101111110010087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555555005023 + 50555555005024.
It is an arithmetic number, because the mean of its divisors is an integer number (50555555005024).
Almost surely, 2101111110010047 is an apocalyptic number.
101111110010047 is a deficient number, since it is larger than the sum of its proper divisors (1).
101111110010047 is an equidigital number, since it uses as much as digits as its factorization.
101111110010047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28, while the sum is 19.
Adding to 101111110010047 its reverse (740010011111101), we get a palindrome (841121121121148).
The spelling of 101111110010047 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, ten thousand, forty-seven".
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