Base | Representation |
---|---|
bin | 10110111111010111000011… |
… | …110011001110000111111011 |
3 | 111021000010110002222211022022 |
4 | 112333113003303032013323 |
5 | 101223101023141140301 |
6 | 555013445220145055 |
7 | 30204015365150264 |
oct | 2677270363160773 |
9 | 437003402884268 |
10 | 101111110099451 |
11 | 2a242a87765341 |
12 | b41001623818b |
13 | 44559768b725a |
14 | 1ad7b37a4996b |
15 | ba51ea80bd1b |
hex | 5bf5c3cce1fb |
101111110099451 has 2 divisors, whose sum is σ = 101111110099452. Its totient is φ = 101111110099450.
The previous prime is 101111110099421. The next prime is 101111110099457. The reversal of 101111110099451 is 154990011111101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101111110099451 is a prime.
It is a super-2 number, since 2×1011111100994512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101111110099457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555555049725 + 50555555049726.
It is an arithmetic number, because the mean of its divisors is an integer number (50555555049726).
Almost surely, 2101111110099451 is an apocalyptic number.
101111110099451 is a deficient number, since it is larger than the sum of its proper divisors (1).
101111110099451 is an equidigital number, since it uses as much as digits as its factorization.
101111110099451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 35.
The spelling of 101111110099451 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, ninety-nine thousand, four hundred fifty-one".
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