Base | Representation |
---|---|
bin | 10110111111010111000011… |
… | …110011001110001000000001 |
3 | 111021000010110002222211022112 |
4 | 112333113003303032020001 |
5 | 101223101023141140312 |
6 | 555013445220145105 |
7 | 30204015365150303 |
oct | 2677270363161001 |
9 | 437003402884275 |
10 | 101111110099457 |
11 | 2a242a87765347 |
12 | b410016238195 |
13 | 44559768b7263 |
14 | 1ad7b37a49973 |
15 | ba51ea80bd22 |
hex | 5bf5c3cce201 |
101111110099457 has 2 divisors, whose sum is σ = 101111110099458. Its totient is φ = 101111110099456.
The previous prime is 101111110099451. The next prime is 101111110099469. The reversal of 101111110099457 is 754990011111101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100039023806401 + 1072086293056 = 10001951^2 + 1035416^2 .
It is a cyclic number.
It is not a de Polignac number, because 101111110099457 - 214 = 101111110083073 is a prime.
It is not a weakly prime, because it can be changed into another prime (101111110099451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555555049728 + 50555555049729.
It is an arithmetic number, because the mean of its divisors is an integer number (50555555049729).
Almost surely, 2101111110099457 is an apocalyptic number.
It is an amenable number.
101111110099457 is a deficient number, since it is larger than the sum of its proper divisors (1).
101111110099457 is an equidigital number, since it uses as much as digits as its factorization.
101111110099457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 41.
The spelling of 101111110099457 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, ninety-nine thousand, four hundred fifty-seven".
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