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1011111120133 is a prime number
BaseRepresentation
bin11101011011010101110…
…10110100110100000101
310120122212001221210212221
432231222322310310011
5113031223421321013
62052255324212341
7133023163500202
oct16555272646405
93518761853787
101011111120133
1135a89a95aa04
12143b6309a0b1
137446922b33a
1436d1bda0ca9
151b47be5508d
hexeb6aeb4d05

1011111120133 has 2 divisors, whose sum is σ = 1011111120134. Its totient is φ = 1011111120132.

The previous prime is 1011111120109. The next prime is 1011111120161. The reversal of 1011111120133 is 3310211111101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1011104658369 + 6461764 = 1005537^2 + 2542^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011111120133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011111120433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505555560066 + 505555560067.

It is an arithmetic number, because the mean of its divisors is an integer number (505555560067).

Almost surely, 21011111120133 is an apocalyptic number.

It is an amenable number.

1011111120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011111120133 is an equidigital number, since it uses as much as digits as its factorization.

1011111120133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1011111120133 its reverse (3310211111101), we get a palindrome (4321322231234).

The spelling of 1011111120133 in words is "one trillion, eleven billion, one hundred eleven million, one hundred twenty thousand, one hundred thirty-three".