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101111122000043 is a prime number
BaseRepresentation
bin10110111111010111000100…
…100000100111100010101011
3111021000010110221101102211222
4112333113010200213202223
5101223101034213000133
6555013450323212255
730204015601254011
oct2677270440474253
9437003427342758
10101111122000043
112a242a93453441
12b41001a21708b
1344559791c2c1c
141ad7b394668b1
15ba51eb8ace98
hex5bf5c48278ab

101111122000043 has 2 divisors, whose sum is σ = 101111122000044. Its totient is φ = 101111122000042.

The previous prime is 101111122000039. The next prime is 101111122000253. The reversal of 101111122000043 is 340000221111101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101111122000043 - 22 = 101111122000039 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 101111121999985 and 101111122000030.

It is not a weakly prime, because it can be changed into another prime (101111122000543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555561000021 + 50555561000022.

It is an arithmetic number, because the mean of its divisors is an integer number (50555561000022).

Almost surely, 2101111122000043 is an apocalyptic number.

101111122000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

101111122000043 is an equidigital number, since it uses as much as digits as its factorization.

101111122000043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101111122000043 its reverse (340000221111101), we get a palindrome (441111343111144).

The spelling of 101111122000043 in words is "one hundred one trillion, one hundred eleven billion, one hundred twenty-two million, forty-three", and thus it is an aban number.