Base | Representation |
---|---|
bin | 1001001100100010111011… |
… | …1010101001100011000011 |
3 | 1022210121121202000101222012 |
4 | 2103020232322221203003 |
5 | 2311130103334010001 |
6 | 33300554344003135 |
7 | 2062335323064602 |
oct | 223105672514303 |
9 | 38717552011865 |
10 | 10111140141251 |
11 | 3249124016126 |
12 | 11737344604ab |
13 | 58462691c006 |
14 | 26d54b8dda39 |
15 | 1280321a02bb |
hex | 9322eea98c3 |
10111140141251 has 2 divisors, whose sum is σ = 10111140141252. Its totient is φ = 10111140141250.
The previous prime is 10111140141233. The next prime is 10111140141359. The reversal of 10111140141251 is 15214104111101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10111140141251 - 242 = 5713093630147 is a prime.
It is not a weakly prime, because it can be changed into another prime (10111140144251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055570070625 + 5055570070626.
It is an arithmetic number, because the mean of its divisors is an integer number (5055570070626).
Almost surely, 210111140141251 is an apocalyptic number.
10111140141251 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111140141251 is an equidigital number, since it uses as much as digits as its factorization.
10111140141251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 160, while the sum is 23.
Adding to 10111140141251 its reverse (15214104111101), we get a palindrome (25325244252352).
The spelling of 10111140141251 in words is "ten trillion, one hundred eleven billion, one hundred forty million, one hundred forty-one thousand, two hundred fifty-one".
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