10111200000111 has 40 divisors (see below), whose sum is σ = 17545140696864. Its totient is φ = 5683110050880.

The previous prime is 10111200000103. The next prime is 10111200000113. The reversal of 10111200000111 is 11100000211101.

It is not a de Polignac number, because 10111200000111 - 2³ = 10111200000103 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 10111200000093 and 10111200000102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111200000113) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 146135940 + ... + 146205113.

Almost surely, 2^{10111200000111} is an apocalyptic number.

10111200000111 is a deficient number, since it is larger than the sum of its proper divisors (7433940696753).

10111200000111 is an equidigital number, since it uses as much as digits as its factorization.

10111200000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292341133 (or 292341124 counting only the distinct ones).

The product of its (nonzero) digits is 2, while the sum is 9.

Adding to 10111200000111 its reverse (11100000211101), we get a palindrome (21211200211212).

The spelling of 10111200000111 in words is "ten trillion, one hundred eleven billion, two hundred million, one hundred eleven", and thus it is an aban number.