101112114127 has 2 divisors, whose sum is σ = 101112114128. Its totient is φ = 101112114126.

The previous prime is 101112114107. The next prime is 101112114143. The reversal of 101112114127 is 721411211101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101112114127 - 2¹⁵ = 101112081359 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101112114098 and 101112114107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101112114107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556057063 + 50556057064.

It is an arithmetic number, because the mean of its divisors is an integer number (50556057064).

Almost surely, 2^101112114127 is an apocalyptic number.

101112114127 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112114127 is an equidigital number, since it uses as much as digits as its factorization.

101112114127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 22.

Adding to 101112114127 its reverse (721411211101), we get a palindrome (822523325228).

The spelling of 101112114127 in words is "one hundred one billion, one hundred twelve million, one hundred fourteen thousand, one hundred twenty-seven".