101112120000007 has 2 divisors, whose sum is σ = 101112120000008. Its totient is φ = 101112120000006.

The previous prime is 101112119999981. The next prime is 101112120000109. The reversal of 101112120000007 is 700000021211101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101112120000007 - 2¹⁵ = 101112119967239 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101112120007007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556060000003 + 50556060000004.

It is an arithmetic number, because the mean of its divisors is an integer number (50556060000004).

Almost surely, 2^{101112120000007} is an apocalyptic number.

101112120000007 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112120000007 is an equidigital number, since it uses as much as digits as its factorization.

101112120000007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 101112120000007 its reverse (700000021211101), we get a palindrome (801112141211108).

The spelling of 101112120000007 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty million, seven", and thus it is an aban number.