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101112121021207 is a prime number
BaseRepresentation
bin10110111111011000000000…
…000011100101001100010111
3111021000020001120012222020211
4112333120000003211030113
5101223110110440134312
6555014133411510251
730204052421640112
oct2677300003451427
9437006046188224
10101112121021207
112a24345636886a
12b4102588b8387
134455aa81796ca
141ad7bd1ddb579
15ba52594493a7
hex5bf6000e5317

101112121021207 has 2 divisors, whose sum is σ = 101112121021208. Its totient is φ = 101112121021206.

The previous prime is 101112121021201. The next prime is 101112121021217. The reversal of 101112121021207 is 702120121211101.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101112121021207 is a prime.

It is a super-2 number, since 2×1011121210212072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101112121021201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556060510603 + 50556060510604.

It is an arithmetic number, because the mean of its divisors is an integer number (50556060510604).

Almost surely, 2101112121021207 is an apocalyptic number.

101112121021207 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112121021207 is an equidigital number, since it uses as much as digits as its factorization.

101112121021207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 22.

Adding to 101112121021207 its reverse (702120121211101), we get a palindrome (803232242232308).

The spelling of 101112121021207 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty-one million, twenty-one thousand, two hundred seven".