Base | Representation |
---|---|
bin | 10110111111011000000000… |
… | …000011100101001100010111 |
3 | 111021000020001120012222020211 |
4 | 112333120000003211030113 |
5 | 101223110110440134312 |
6 | 555014133411510251 |
7 | 30204052421640112 |
oct | 2677300003451427 |
9 | 437006046188224 |
10 | 101112121021207 |
11 | 2a24345636886a |
12 | b4102588b8387 |
13 | 4455aa81796ca |
14 | 1ad7bd1ddb579 |
15 | ba52594493a7 |
hex | 5bf6000e5317 |
101112121021207 has 2 divisors, whose sum is σ = 101112121021208. Its totient is φ = 101112121021206.
The previous prime is 101112121021201. The next prime is 101112121021217. The reversal of 101112121021207 is 702120121211101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101112121021207 is a prime.
It is a super-2 number, since 2×1011121210212072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101112121021201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556060510603 + 50556060510604.
It is an arithmetic number, because the mean of its divisors is an integer number (50556060510604).
Almost surely, 2101112121021207 is an apocalyptic number.
101112121021207 is a deficient number, since it is larger than the sum of its proper divisors (1).
101112121021207 is an equidigital number, since it uses as much as digits as its factorization.
101112121021207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 101112121021207 its reverse (702120121211101), we get a palindrome (803232242232308).
The spelling of 101112121021207 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty-one million, twenty-one thousand, two hundred seven".
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