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101112121120963 is a prime number
BaseRepresentation
bin10110111111011000000000…
…000011111101100011000011
3111021000020001120102001002111
4112333120000003331203003
5101223110111001332323
6555014133414000151
730204052422534001
oct2677300003754303
9437006046361074
10101112121120963
112a243456426807
12b410258946057
134455aa81b2c34
141ad7bd2025a71
15ba5259468c0d
hex5bf6000fd8c3

101112121120963 has 2 divisors, whose sum is σ = 101112121120964. Its totient is φ = 101112121120962.

The previous prime is 101112121120951. The next prime is 101112121121027. The reversal of 101112121120963 is 369021121211101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101112121120963 - 225 = 101112087566531 is a prime.

It is a super-2 number, since 2×1011121211209632 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101112121120463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556060560481 + 50556060560482.

It is an arithmetic number, because the mean of its divisors is an integer number (50556060560482).

Almost surely, 2101112121120963 is an apocalyptic number.

101112121120963 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112121120963 is an equidigital number, since it uses as much as digits as its factorization.

101112121120963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 31.

The spelling of 101112121120963 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty-one million, one hundred twenty thousand, nine hundred sixty-three".