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10111212161 is a prime number
BaseRepresentation
bin10010110101010110…
…01101101010000001
3222002200000210112022
421122223031222001
5131201432242121
64351154211225
7505364612441
oct113253155201
928080023468
1010111212161
114319574396
121b62283b15
13c51a5849b
146bcc32121
153e2a29aab
hex25aacda81

10111212161 has 2 divisors, whose sum is σ = 10111212162. Its totient is φ = 10111212160.

The previous prime is 10111212127. The next prime is 10111212173. The reversal of 10111212161 is 16121211101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9606940225 + 504271936 = 98015^2 + 22456^2 .

It is an emirp because it is prime and its reverse (16121211101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10111212161 is a prime.

It is a super-2 number, since 2×101112121612 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10111212101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055606080 + 5055606081.

It is an arithmetic number, because the mean of its divisors is an integer number (5055606081).

Almost surely, 210111212161 is an apocalyptic number.

It is an amenable number.

10111212161 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111212161 is an equidigital number, since it uses as much as digits as its factorization.

10111212161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 10111212161 its reverse (16121211101), we get a palindrome (26232423262).

The spelling of 10111212161 in words is "ten billion, one hundred eleven million, two hundred twelve thousand, one hundred sixty-one".