101112123113 has 4 divisors (see below), whose sum is σ = 102039757380. Its totient is φ = 100184488848.

The previous prime is 101112123109. The next prime is 101112123127. The reversal of 101112123113 is 311321211101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42484217689 + 58627905424 = 206117^2 + 242132^2 .

It is a cyclic number.

It is not a de Polignac number, because 101112123113 - 2² = 101112123109 is a prime.

It is a super-2 number, since 2×101112123113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101112123091 and 101112123100.

It is not an unprimeable number, because it can be changed into a prime (101112123103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 463816970 + ... + 463817187.

It is an arithmetic number, because the mean of its divisors is an integer number (25509939345).

Almost surely, 2^101112123113 is an apocalyptic number.

It is an amenable number.

101112123113 is a deficient number, since it is larger than the sum of its proper divisors (927634267).

101112123113 is an equidigital number, since it uses as much as digits as its factorization.

101112123113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 927634266.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 101112123113 its reverse (311321211101), we get a palindrome (412433334214).

The spelling of 101112123113 in words is "one hundred one billion, one hundred twelve million, one hundred twenty-three thousand, one hundred thirteen".