101112132413 has 2 divisors, whose sum is σ = 101112132414. Its totient is φ = 101112132412.

The previous prime is 101112132403. The next prime is 101112132427. The reversal of 101112132413 is 314231211101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54776125849 + 46336006564 = 234043^2 + 215258^2 .

It is a cyclic number.

It is not a de Polignac number, because 101112132413 - 2¹⁶ = 101112066877 is a prime.

It is a super-2 number, since 2×101112132413² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101112132403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556066206 + 50556066207.

It is an arithmetic number, because the mean of its divisors is an integer number (50556066207).

Almost surely, 2^101112132413 is an apocalyptic number.

It is an amenable number.

101112132413 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112132413 is an equidigital number, since it uses as much as digits as its factorization.

101112132413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 101112132413 its reverse (314231211101), we get a palindrome (415343343514).

The spelling of 101112132413 in words is "one hundred one billion, one hundred twelve million, one hundred thirty-two thousand, four hundred thirteen".