101112243303 has 4 divisors (see below), whose sum is σ = 134816324408. Its totient is φ = 67408162200.

The previous prime is 101112243301. The next prime is 101112243307. The reversal of 101112243303 is 303342211101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 101112243303 - 2¹ = 101112243301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101112243303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101112243301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16852040548 + ... + 16852040553.

It is an arithmetic number, because the mean of its divisors is an integer number (33704081102).

Almost surely, 2^101112243303 is an apocalyptic number.

101112243303 is a deficient number, since it is larger than the sum of its proper divisors (33704081105).

101112243303 is an equidigital number, since it uses as much as digits as its factorization.

101112243303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33704081104.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 101112243303 its reverse (303342211101), we get a palindrome (404454454404).

The spelling of 101112243303 in words is "one hundred one billion, one hundred twelve million, two hundred forty-three thousand, three hundred three".