101112332113 has 4 divisors (see below), whose sum is σ = 108890203828. Its totient is φ = 93334460400.

The previous prime is 101112332107. The next prime is 101112332171. The reversal of 101112332113 is 311233211101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 54050670144 + 47061661969 = 232488^2 + 216937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101112332113 is a prime.

It is a super-2 number, since 2×101112332113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101112332183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3888935838 + ... + 3888935863.

It is an arithmetic number, because the mean of its divisors is an integer number (27222550957).

Almost surely, 2^101112332113 is an apocalyptic number.

101112332113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

101112332113 is a deficient number, since it is larger than the sum of its proper divisors (7777871715).

101112332113 is an equidigital number, since it uses as much as digits as its factorization.

101112332113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7777871714.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 101112332113 its reverse (311233211101), we get a palindrome (412345543214).

The spelling of 101112332113 in words is "one hundred one billion, one hundred twelve million, three hundred thirty-two thousand, one hundred thirteen".