101113001131 has 4 divisors (see below), whose sum is σ = 101458096992. Its totient is φ = 100767905272.

The previous prime is 101113001113. The next prime is 101113001137. The reversal of 101113001131 is 131100311101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131100311101 = 167 ⋅785031803.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101113001131 is a prime.

It is a super-2 number, since 2×101113001131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101113001137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172547491 + ... + 172548076.

It is an arithmetic number, because the mean of its divisors is an integer number (25364524248).

Almost surely, 2^101113001131 is an apocalyptic number.

101113001131 is a deficient number, since it is larger than the sum of its proper divisors (345095861).

101113001131 is an equidigital number, since it uses as much as digits as its factorization.

101113001131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 345095860.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 101113001131 its reverse (131100311101), we get a palindrome (232213312232).

The spelling of 101113001131 in words is "one hundred one billion, one hundred thirteen million, one thousand, one hundred thirty-one".