10111302137 has 2 divisors, whose sum is σ = 10111302138. Its totient is φ = 10111302136.

The previous prime is 10111302127. The next prime is 10111302163. The reversal of 10111302137 is 73120311101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9397557481 + 713744656 = 96941^2 + 26716^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111302137 - 2¹⁸ = 10111039993 is a prime.

It is not a weakly prime, because it can be changed into another prime (10111302107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055651068 + 5055651069.

It is an arithmetic number, because the mean of its divisors is an integer number (5055651069).

Almost surely, 2^10111302137 is an apocalyptic number.

It is an amenable number.

10111302137 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111302137 is an equidigital number, since it uses as much as digits as its factorization.

10111302137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 20.

Adding to 10111302137 its reverse (73120311101), we get a palindrome (83231613238).

The spelling of 10111302137 in words is "ten billion, one hundred eleven million, three hundred two thousand, one hundred thirty-seven".