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10111302127 is a prime number
BaseRepresentation
bin10010110101010111…
…00011100111101111
3222002200012100221101
421122223203213233
5131201443132002
64351200143531
7505365435643
oct113253434757
928080170841
1010111302127
114319625a43
121b62307ba7
13c51a8a414
146bcc56c23
153e2a46587
hex25aae39ef

10111302127 has 2 divisors, whose sum is σ = 10111302128. Its totient is φ = 10111302126.

The previous prime is 10111302107. The next prime is 10111302137. The reversal of 10111302127 is 72120311101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10111302127 - 223 = 10102913519 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111302107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055651063 + 5055651064.

It is an arithmetic number, because the mean of its divisors is an integer number (5055651064).

Almost surely, 210111302127 is an apocalyptic number.

10111302127 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111302127 is an equidigital number, since it uses as much as digits as its factorization.

10111302127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 10111302127 its reverse (72120311101), we get a palindrome (82231613228).

The spelling of 10111302127 in words is "ten billion, one hundred eleven million, three hundred two thousand, one hundred twenty-seven".