10111312221113 has 4 divisors (see below), whose sum is σ = 10643486548560. Its totient is φ = 9579137893668.

The previous prime is 10111312221107. The next prime is 10111312221133. The reversal of 10111312221113 is 31112221311101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10111312221113 - 2²⁸ = 10111043785657 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10111312221133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266087163695 + ... + 266087163732.

It is an arithmetic number, because the mean of its divisors is an integer number (2660871637140).

Almost surely, 2^{10111312221113} is an apocalyptic number.

It is an amenable number.

10111312221113 is a deficient number, since it is larger than the sum of its proper divisors (532174327447).

10111312221113 is an equidigital number, since it uses as much as digits as its factorization.

10111312221113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 532174327446.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 10111312221113 its reverse (31112221311101), we get a palindrome (41223533532214).

The spelling of 10111312221113 in words is "ten trillion, one hundred eleven billion, three hundred twelve million, two hundred twenty-one thousand, one hundred thirteen".