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10111314201 = 37942663773
BaseRepresentation
bin10010110101010111…
…00110100100011001
3222002200012222111120
421122223212210121
5131201444023301
64351200315453
7505365516102
oct113253464431
928080188446
1010111314201
11431963401a
121b62312b89
13c51a92a71
146bcc5b3a9
153e2a49e36
hex25aae6919

10111314201 has 8 divisors (see below), whose sum is σ = 13652407680. Its totient is φ = 6655548432.

The previous prime is 10111314167. The next prime is 10111314217. The reversal of 10111314201 is 10241311101.

10111314201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10111314201 - 29 = 10111313689 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10111314221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21331650 + ... + 21332123.

It is an arithmetic number, because the mean of its divisors is an integer number (1706550960).

Almost surely, 210111314201 is an apocalyptic number.

It is an amenable number.

10111314201 is a deficient number, since it is larger than the sum of its proper divisors (3541093479).

10111314201 is an equidigital number, since it uses as much as digits as its factorization.

10111314201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42663855.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 10111314201 its reverse (10241311101), we get a palindrome (20352625302).

The spelling of 10111314201 in words is "ten billion, one hundred eleven million, three hundred fourteen thousand, two hundred one".

Divisors: 1 3 79 237 42663773 127991319 3370438067 10111314201