101113144130 has 8 divisors (see below), whose sum is σ = 182003659452. Its totient is φ = 40445257648.

The previous prime is 101113144117. The next prime is 101113144159. The reversal of 101113144130 is 31441311101.

It can be written as a sum of positive squares in 2 ways, for example, as 97032873001 + 4080271129 = 311501^2 + 63877^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5055657197 + ... + 5055657216.

Almost surely, 2^101113144130 is an apocalyptic number.

101113144130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101113144130 is a deficient number, since it is larger than the sum of its proper divisors (80890515322).

101113144130 is a wasteful number, since it uses less digits than its factorization.

101113144130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10111314420.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 101113144130 its reverse (31441311101), we get a palindrome (132554455231).

The spelling of 101113144130 in words is "one hundred one billion, one hundred thirteen million, one hundred forty-four thousand, one hundred thirty".