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101113222113 = 3211234802457
BaseRepresentation
bin101111000101011010…
…0010101001111100001
3100122222202100212220100
41132022310111033201
53124034441101423
6114241211133013
710206452131011
oct1361264251741
9318882325810
10101113222113
1139977861382
121771a744169
1396c533c757
144c72c41c41
15296bd33343
hex178ad153e1

101113222113 has 6 divisors (see below), whose sum is σ = 146052431954. Its totient is φ = 67408814736.

The previous prime is 101113222061. The next prime is 101113222117. The reversal of 101113222113 is 311222311101.

It can be written as a sum of positive squares in only one way, i.e., 84490792929 + 16622429184 = 290673^2 + 128928^2 .

It is not a de Polignac number, because 101113222113 - 225 = 101079667681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101113222117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5617401220 + ... + 5617401237.

Almost surely, 2101113222113 is an apocalyptic number.

It is an amenable number.

101113222113 is a deficient number, since it is larger than the sum of its proper divisors (44939209841).

101113222113 is a wasteful number, since it uses less digits than its factorization.

101113222113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11234802463 (or 11234802460 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 101113222113 its reverse (311222311101), we get a palindrome (412335533214).

The spelling of 101113222113 in words is "one hundred one billion, one hundred thirteen million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 9 11234802457 33704407371 101113222113