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10111333320149 is a prime number
BaseRepresentation
bin1001001100100011101001…
…1011100100010111010101
31022210122010012111220121012
42103020322123210113111
52311131002312221044
633301025444302005
72062343160062435
oct223107233442725
938718105456535
1010111333320149
11324921306a306
1211737890a1905
13584657958659
1426d5694282c5
1512804410d59e
hex9323a6e45d5

10111333320149 has 2 divisors, whose sum is σ = 10111333320150. Its totient is φ = 10111333320148.

The previous prime is 10111333320041. The next prime is 10111333320211. The reversal of 10111333320149 is 94102333311101.

10111333320149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9821598727249 + 289734592900 = 3133943^2 + 538270^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10111333320149 is a prime.

It is a super-2 number, since 2×101113333201492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111333320749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055666660074 + 5055666660075.

It is an arithmetic number, because the mean of its divisors is an integer number (5055666660075).

Almost surely, 210111333320149 is an apocalyptic number.

It is an amenable number.

10111333320149 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111333320149 is an equidigital number, since it uses as much as digits as its factorization.

10111333320149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 10111333320149 in words is "ten trillion, one hundred eleven billion, three hundred thirty-three million, three hundred twenty thousand, one hundred forty-nine".