10111399999 has 4 divisors (see below), whose sum is σ = 10282779720. Its totient is φ = 9940020280.

The previous prime is 10111399981. The next prime is 10111400009. The reversal of 10111399999 is 99999311101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 99999311101 = 97 ⋅1030920733.

It is not a de Polignac number, because 10111399999 - 2⁵ = 10111399967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111399919) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85689772 + ... + 85689889.

It is an arithmetic number, because the mean of its divisors is an integer number (2570694930).

Almost surely, 2^10111399999 is an apocalyptic number.

10111399999 is a deficient number, since it is larger than the sum of its proper divisors (171379721).

10111399999 is an equidigital number, since it uses as much as digits as its factorization.

10111399999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171379720.

The product of its (nonzero) digits is 177147, while the sum is 52.

The spelling of 10111399999 in words is "ten billion, one hundred eleven million, three hundred ninety-nine thousand, nine hundred ninety-nine".