Base | Representation |
---|---|
bin | 101111000101011011… |
… | …1110010111110100111 |
3 | 100122222211002000202111 |
4 | 1132022313302332213 |
5 | 3124040204132333 |
6 | 114241242421451 |
7 | 10206462632632 |
oct | 1361267627647 |
9 | 318884060674 |
10 | 101114130343 |
11 | 39978321786 |
12 | 1771ab01887 |
13 | 96c5599c75 |
14 | 4c72ddac19 |
15 | 296be624cd |
hex | 178adf2fa7 |
101114130343 has 2 divisors, whose sum is σ = 101114130344. Its totient is φ = 101114130342.
The previous prime is 101114130317. The next prime is 101114130373. The reversal of 101114130343 is 343031411101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101114130343 - 25 = 101114130311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101114130373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50557065171 + 50557065172.
It is an arithmetic number, because the mean of its divisors is an integer number (50557065172).
Almost surely, 2101114130343 is an apocalyptic number.
101114130343 is a deficient number, since it is larger than the sum of its proper divisors (1).
101114130343 is an equidigital number, since it uses as much as digits as its factorization.
101114130343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 101114130343 its reverse (343031411101), we get a palindrome (444145541444).
The spelling of 101114130343 in words is "one hundred one billion, one hundred fourteen million, one hundred thirty thousand, three hundred forty-three".
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