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101114130703 = 197513269699
BaseRepresentation
bin101111000101011011…
…1110011000100001111
3100122222211002001020211
41132022313303010033
53124040204140303
6114241242423251
710206462633655
oct1361267630417
9318884061224
10101114130703
1139978321a83
121771ab01b27
1396c559a191
144c72ddadd5
15296be6266d
hex178adf310f

101114130703 has 4 divisors (see below), whose sum is σ = 101627400600. Its totient is φ = 100600860808.

The previous prime is 101114130679. The next prime is 101114130721. The reversal of 101114130703 is 307031411101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101114130703 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101114130773) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256634653 + ... + 256635046.

It is an arithmetic number, because the mean of its divisors is an integer number (25406850150).

Almost surely, 2101114130703 is an apocalyptic number.

101114130703 is a deficient number, since it is larger than the sum of its proper divisors (513269897).

101114130703 is an equidigital number, since it uses as much as digits as its factorization.

101114130703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 513269896.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 101114130703 its reverse (307031411101), we get a palindrome (408145541804).

The spelling of 101114130703 in words is "one hundred one billion, one hundred fourteen million, one hundred thirty thousand, seven hundred three".

Divisors: 1 197 513269699 101114130703