10111611113 has 2 divisors, whose sum is σ = 10111611114. Its totient is φ = 10111611112.

The previous prime is 10111611089. The next prime is 10111611127. The reversal of 10111611113 is 31111611101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8429626969 + 1681984144 = 91813^2 + 41012^2 .

It is an emirp because it is prime and its reverse (31111611101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111611113 - 2⁸ = 10111610857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10111611091 and 10111611100.

It is not a weakly prime, because it can be changed into another prime (10111611143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055805556 + 5055805557.

It is an arithmetic number, because the mean of its divisors is an integer number (5055805557).

Almost surely, 2^10111611113 is an apocalyptic number.

It is an amenable number.

10111611113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111611113 is an equidigital number, since it uses as much as digits as its factorization.

10111611113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 17.

The spelling of 10111611113 in words is "ten billion, one hundred eleven million, six hundred eleven thousand, one hundred thirteen".