1011200111321 has 2 divisors, whose sum is σ = 1011200111322. Its totient is φ = 1011200111320.

The previous prime is 1011200111303. The next prime is 1011200111323. The reversal of 1011200111321 is 1231110021101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 535734699721 + 475465411600 = 731939^2 + 689540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011200111321 is a prime.

It is a super-3 number, since 3×1011200111321³ (a number of 37 digits) contains 333 as substring.

Together with 1011200111323, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011200111296 and 1011200111305.

It is not a weakly prime, because it can be changed into another prime (1011200111323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600055660 + 505600055661.

It is an arithmetic number, because the mean of its divisors is an integer number (505600055661).

Almost surely, 2^{1011200111321} is an apocalyptic number.

It is an amenable number.

1011200111321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011200111321 is an equidigital number, since it uses as much as digits as its factorization.

1011200111321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1011200111321 its reverse (1231110021101), we get a palindrome (2242310132422).

The spelling of 1011200111321 in words is "one trillion, eleven billion, two hundred million, one hundred eleven thousand, three hundred twenty-one".