101120014303130 has 8 divisors (see below), whose sum is σ = 182016025745652. Its totient is φ = 40448005721248.

The previous prime is 101120014303097. The next prime is 101120014303163. The reversal of 101120014303130 is 31303410021101.

It is an interprime number because it is at equal distance from previous prime (101120014303097) and next prime (101120014303163).

It can be written as a sum of positive squares in 2 ways, for example, as 101111531708929 + 8482594201 = 10055423^2 + 92101^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5056000715147 + ... + 5056000715166.

Almost surely, 2^{101120014303130} is an apocalyptic number.

101120014303130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101120014303130 is a deficient number, since it is larger than the sum of its proper divisors (80896011442522).

101120014303130 is a wasteful number, since it uses less digits than its factorization.

101120014303130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10112001430320.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 101120014303130 its reverse (31303410021101), we get a palindrome (132423424324231).

The spelling of 101120014303130 in words is "one hundred one trillion, one hundred twenty billion, fourteen million, three hundred three thousand, one hundred thirty".