101120022220121 has 4 divisors (see below), whose sum is σ = 101156252972544. Its totient is φ = 101083791467700.

The previous prime is 101120022220109. The next prime is 101120022220169. The reversal of 101120022220121 is 121022220021101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101120022220121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101120022220121.

It is not an unprimeable number, because it can be changed into a prime (101120022225121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18115372025 + ... + 18115377606.

It is an arithmetic number, because the mean of its divisors is an integer number (25289063243136).

Almost surely, 2^{101120022220121} is an apocalyptic number.

It is an amenable number.

101120022220121 is a deficient number, since it is larger than the sum of its proper divisors (36230752423).

101120022220121 is an equidigital number, since it uses as much as digits as its factorization.

101120022220121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36230752422.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 101120022220121 its reverse (121022220021101), we get a palindrome (222142242241222).

The spelling of 101120022220121 in words is "one hundred one trillion, one hundred twenty billion, twenty-two million, two hundred twenty thousand, one hundred twenty-one".