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101120023313 is a prime number
BaseRepresentation
bin101111000101100111…
…0010001101100010001
3100200000020011102101122
41132023032101230101
53124043211221223
6114242013012025
710206564005411
oct1361316215421
9320006142348
10101120023313
1139980687201
1217720a84015
1396c688132a
144c73ad2641
15296c7285c8
hex178b391b11

101120023313 has 2 divisors, whose sum is σ = 101120023314. Its totient is φ = 101120023312.

The previous prime is 101120023231. The next prime is 101120023343. The reversal of 101120023313 is 313320021101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76711273024 + 24408750289 = 276968^2 + 156233^2 .

It is an emirp because it is prime and its reverse (313320021101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101120023313 - 216 = 101119957777 is a prime.

It is a super-2 number, since 2×1011200233132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101120023291 and 101120023300.

It is not a weakly prime, because it can be changed into another prime (101120023343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560011656 + 50560011657.

It is an arithmetic number, because the mean of its divisors is an integer number (50560011657).

Almost surely, 2101120023313 is an apocalyptic number.

It is an amenable number.

101120023313 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120023313 is an equidigital number, since it uses as much as digits as its factorization.

101120023313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 101120023313 its reverse (313320021101), we get a palindrome (414440044414).

The spelling of 101120023313 in words is "one hundred one billion, one hundred twenty million, twenty-three thousand, three hundred thirteen".