101120113 has 2 divisors, whose sum is σ = 101120114. Its totient is φ = 101120112.

The previous prime is 101120099. The next prime is 101120141. The reversal of 101120113 is 311021101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75637809 + 25482304 = 8697^2 + 5048^2 .

It is an emirp because it is prime and its reverse (311021101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101120113 - 2²¹ = 99022961 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101120113.

It is not a weakly prime, because it can be changed into another prime (101120153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560056 + 50560057.

It is an arithmetic number, because the mean of its divisors is an integer number (50560057).

Almost surely, 2^101120113 is an apocalyptic number.

It is an amenable number.

101120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120113 is an equidigital number, since it uses as much as digits as its factorization.

101120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 101120113 is about 10055.8496906030. The cubic root of 101120113 is about 465.8854873445.

Adding to 101120113 its reverse (311021101), we get a palindrome (412141214).

The spelling of 101120113 in words is "one hundred one million, one hundred twenty thousand, one hundred thirteen".