1011201131311 has 4 divisors (see below), whose sum is σ = 1155658435792. Its totient is φ = 866743826832.

The previous prime is 1011201131263. The next prime is 1011201131329. The reversal of 1011201131311 is 1131311021101.

1011201131311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011201131311 - 2¹⁵ = 1011201098543 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011201131711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72228652230 + ... + 72228652243.

It is an arithmetic number, because the mean of its divisors is an integer number (288914608948).

Almost surely, 2^{1011201131311} is an apocalyptic number.

1011201131311 is a deficient number, since it is larger than the sum of its proper divisors (144457304481).

1011201131311 is an equidigital number, since it uses as much as digits as its factorization.

1011201131311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144457304480.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1011201131311 its reverse (1131311021101), we get a palindrome (2142512152412).

The spelling of 1011201131311 in words is "one trillion, eleven billion, two hundred one million, one hundred thirty-one thousand, three hundred eleven".