Search a number
-
+
1011201222012 = 2231914281310559
BaseRepresentation
bin11101011011100000100…
…10100010010101111100
310120200002100111110102120
432231300102202111330
5113031420003101022
62052312303322540
7133025336365662
oct16556022422574
93520070443376
101011201222012
1135a936800873
12143b892b0450
1374481ab7767
1436d29d36c32
151b484d01d5c
hexeb704a257c

1011201222012 has 48 divisors (see below), whose sum is σ = 2483834035200. Its totient is φ = 319303313280.

The previous prime is 1011201222011. The next prime is 1011201222049. The reversal of 1011201222012 is 2102221021101.

1011201222012 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×10112012220123 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1011201221982 and 1011201222000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011201222011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3100789 + ... + 3411347.

It is an arithmetic number, because the mean of its divisors is an integer number (51746542400).

Almost surely, 21011201222012 is an apocalyptic number.

1011201222012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1011201222012 is an abundant number, since it is smaller than the sum of its proper divisors (1472632813188).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011201222012 is a wasteful number, since it uses less digits than its factorization.

1011201222012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 324866 (or 324864 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 1011201222012 its reverse (2102221021101), we get a palindrome (3113422243113).

The spelling of 1011201222012 in words is "one trillion, eleven billion, two hundred one million, two hundred twenty-two thousand, twelve".

Divisors: 1 2 3 4 6 12 19 38 57 76 114 228 14281 28562 42843 57124 85686 171372 271339 310559 542678 621118 814017 931677 1085356 1242236 1628034 1863354 3256068 3726708 5900621 11801242 17701863 23602484 35403726 70807452 4435093079 8870186158 13305279237 17740372316 26610558474 53221116948 84266768501 168533537002 252800305503 337067074004 505600611006 1011201222012