Base | Representation |
---|---|
bin | 11101011011100000100… |
… | …10100100110101100111 |
3 | 10120200002100111222110001 |
4 | 32231300102210311213 |
5 | 113031420003412411 |
6 | 2052312303442131 |
7 | 133025336440531 |
oct | 16556022446547 |
9 | 3520070458401 |
10 | 1011201232231 |
11 | 35a936808513 |
12 | 143b892b6347 |
13 | 74481abc2c8 |
14 | 36d29d3a851 |
15 | 1b484d04dc1 |
hex | eb704a4d67 |
1011201232231 has 2 divisors, whose sum is σ = 1011201232232. Its totient is φ = 1011201232230.
The previous prime is 1011201232207. The next prime is 1011201232243. The reversal of 1011201232231 is 1322321021101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011201232231 - 223 = 1011192843623 is a prime.
It is a super-2 number, since 2×10112012322312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1011201232199 and 1011201232208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011201232201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600616115 + 505600616116.
It is an arithmetic number, because the mean of its divisors is an integer number (505600616116).
Almost surely, 21011201232231 is an apocalyptic number.
1011201232231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011201232231 is an equidigital number, since it uses as much as digits as its factorization.
1011201232231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1011201232231 its reverse (1322321021101), we get a palindrome (2333522253332).
The spelling of 1011201232231 in words is "one trillion, eleven billion, two hundred one million, two hundred thirty-two thousand, two hundred thirty-one".
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