Base | Representation |
---|---|
bin | 11101011011100000101… |
… | …01100000100100111101 |
3 | 10120200002101222001021212 |
4 | 32231300111200210331 |
5 | 113031420203014323 |
6 | 2052312332134205 |
7 | 133025346122465 |
oct | 16556025404475 |
9 | 3520071861255 |
10 | 1011202001213 |
11 | 35a937193238 |
12 | 143b89607365 |
13 | 74481ccb321 |
14 | 36d2a09aba5 |
15 | 1b484e07b78 |
hex | eb7056093d |
1011202001213 has 2 divisors, whose sum is σ = 1011202001214. Its totient is φ = 1011202001212.
The previous prime is 1011202001137. The next prime is 1011202001219. The reversal of 1011202001213 is 3121002021101.
1011202001213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 944525465689 + 66676535524 = 971867^2 + 258218^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011202001213 - 220 = 1011200952637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011202001219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505601000606 + 505601000607.
It is an arithmetic number, because the mean of its divisors is an integer number (505601000607).
Almost surely, 21011202001213 is an apocalyptic number.
It is an amenable number.
1011202001213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011202001213 is an equidigital number, since it uses as much as digits as its factorization.
1011202001213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1011202001213 its reverse (3121002021101), we get a palindrome (4132204022314).
The spelling of 1011202001213 in words is "one trillion, eleven billion, two hundred two million, one thousand, two hundred thirteen".
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