1011202012121 has 4 divisors (see below), whose sum is σ = 1155659442432. Its totient is φ = 866744581812.

The previous prime is 1011202012111. The next prime is 1011202012147. The reversal of 1011202012121 is 1212102021101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011202012121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011202012096 and 1011202012105.

It is not an unprimeable number, because it can be changed into a prime (1011202012111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72228715145 + ... + 72228715158.

It is an arithmetic number, because the mean of its divisors is an integer number (288914860608).

Almost surely, 2^{1011202012121} is an apocalyptic number.

It is an amenable number.

1011202012121 is a deficient number, since it is larger than the sum of its proper divisors (144457430311).

1011202012121 is an equidigital number, since it uses as much as digits as its factorization.

1011202012121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144457430310.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 1011202012121 its reverse (1212102021101), we get a palindrome (2223304033222).

The spelling of 1011202012121 in words is "one trillion, eleven billion, two hundred two million, twelve thousand, one hundred twenty-one".