Base | Representation |
---|---|
bin | 11101011011100000101… |
… | …01100011001111110011 |
3 | 10120200002101222121021211 |
4 | 32231300111203033303 |
5 | 113031420203342042 |
6 | 2052312332300551 |
7 | 133025346166405 |
oct | 16556025431763 |
9 | 3520071877254 |
10 | 1011202012147 |
11 | 35a9371a0478 |
12 | 143b89611757 |
13 | 744820032b2 |
14 | 36d2a0a0b75 |
15 | 1b484e0b017 |
hex | eb705633f3 |
1011202012147 has 2 divisors, whose sum is σ = 1011202012148. Its totient is φ = 1011202012146.
The previous prime is 1011202012111. The next prime is 1011202012169. The reversal of 1011202012147 is 7412102021101.
It is a happy number.
It is an a-pointer prime, because the next prime (1011202012169) can be obtained adding 1011202012147 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011202012147 - 219 = 1011201487859 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011202012747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505601006073 + 505601006074.
It is an arithmetic number, because the mean of its divisors is an integer number (505601006074).
Almost surely, 21011202012147 is an apocalyptic number.
1011202012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011202012147 is an equidigital number, since it uses as much as digits as its factorization.
1011202012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 1011202012147 its reverse (7412102021101), we get a palindrome (8423304033248).
The spelling of 1011202012147 in words is "one trillion, eleven billion, two hundred two million, twelve thousand, one hundred forty-seven".
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