101121011143 has 2 divisors, whose sum is σ = 101121011144. Its totient is φ = 101121011142.

The previous prime is 101121011119. The next prime is 101121011149. The reversal of 101121011143 is 341110121101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101121011143 - 2⁵ = 101121011111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101121011149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560505571 + 50560505572.

It is an arithmetic number, because the mean of its divisors is an integer number (50560505572).

Almost surely, 2^101121011143 is an apocalyptic number.

101121011143 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121011143 is an equidigital number, since it uses as much as digits as its factorization.

101121011143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 101121011143 its reverse (341110121101), we get a palindrome (442231132244).

The spelling of 101121011143 in words is "one hundred one billion, one hundred twenty-one million, eleven thousand, one hundred forty-three".