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1011210112013 = 67148310177133
BaseRepresentation
bin11101011011100001101…
…00011100110000001101
310120200002222020010012212
432231300310130300031
5113031424242041023
62052313222040205
7133025505063233
oct16556064346015
93520088203185
101011210112013
1135a940822a82
12143b90279065
13744838ab00a
1436d2b1ac953
151b4859aae78
hexeb70d1cc0d

1011210112013 has 8 divisors (see below), whose sum is σ = 1026994946208. Its totient is φ = 995445635184.

The previous prime is 1011210111997. The next prime is 1011210112051. The reversal of 1011210112013 is 3102110121101.

1011210112013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1011210112013 - 24 = 1011210111997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011210112063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4989206 + ... + 5187927.

It is an arithmetic number, because the mean of its divisors is an integer number (128374368276).

Almost surely, 21011210112013 is an apocalyptic number.

It is an amenable number.

1011210112013 is a deficient number, since it is larger than the sum of its proper divisors (15784834195).

1011210112013 is a wasteful number, since it uses less digits than its factorization.

1011210112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10178683.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1011210112013 its reverse (3102110121101), we get a palindrome (4113320233114).

The spelling of 1011210112013 in words is "one trillion, eleven billion, two hundred ten million, one hundred twelve thousand, thirteen".

Divisors: 1 67 1483 99361 10177133 681867911 15092688239 1011210112013